{"id":1274,"date":"2025-12-22T12:35:29","date_gmt":"2025-12-22T11:35:29","guid":{"rendered":"http:\/\/mymatma.pl\/?p=1274"},"modified":"2025-12-22T12:35:32","modified_gmt":"2025-12-22T11:35:32","slug":"zadanie-113","status":"publish","type":"post","link":"https:\/\/mymatma.pl\/?p=1274","title":{"rendered":"Zadanie 113"},"content":{"rendered":"\n<p><strong>zadanie 11 \u2013 czerwiec 2016 (1pkt)<\/strong><\/p>\n\n\n\n<p>Ci\u0105g (a<sub>n<\/sub>) jest okre\u015blony wzorem a<sub>n<\/sub>=6(n\u221216) dla n\u22651 . Suma dziesi\u0119ciu pocz\u0105tkowych wyraz\u00f3w tego ci\u0105gu jest r\u00f3wna:<\/p>\n\n\n\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-28f84493 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p>a) -54<\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p>b) -126<\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p>c) -630<\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p>d) -270<\/p>\n<\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-28f84493 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n    <div class=\"premium-wrapper-odp\" id=\"odp_69e22dd6c0f5e\">\n        <button class=\"premium-btn-odp\"\n                data-id=\"odp_69e22dd6c0f5e\"\n                style=\"margin-top:10px; padding:12px 20px; background:#28a745; color:#fff; border-radius:25px; border:none; cursor:pointer; font-weight:bold;\">\n            Poka\u017c odpowied\u017a\n        <\/button>\n\n        <div class=\"premium-content-odp\" style=\"display:none; padding:15px; border:1px solid #28a745; margin-top:10px; background:#e6ffe6; border-radius:25px;\">\n            \nPrawid\u0142owa odpowied\u017a to c) -630.\n        <\/div>\n    <\/div>\n    \n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n    <div class=\"premium-wrapper-wyjasnienie\" id=\"wyjasnienie_69e22dd6c0f69\">\n        <button class=\"premium-btn-wyjasnienie\"\n                data-id=\"wyjasnienie_69e22dd6c0f69\"\n                style=\"margin-top:10px; padding:12px 20px; background:#28a745; color:#fff; border-radius:25px; border:none; cursor:pointer; font-weight:bold;\">\n            Poka\u017c wyja\u015bnienie\n        <\/button>\n\n        <div class=\"premium-content-wyjasnienie\" style=\"display:none; padding:15px; border:1px solid #28a745; margin-top:10px; background:#e6ffe6; border-radius:25px;\">\n            \n<h3>Wyja\u015bnienie<\/h3>\n\n<p>Ci\u0105g arytmetyczny jest okre\u015blony wzorem:<\/p>\n\n<p style=\"text-align:center;\">\na<sub>n<\/sub> = 6(n \u2212 16)\n<\/p>\n\n<p>Najpierw obliczamy kilka potrzebnych warto\u015bci:<\/p>\n\n<h4>1. Obliczamy pierwszy wyraz ci\u0105gu<\/h4>\n\n<p style=\"text-align:center;\">\na<sub>1<\/sub> = 6(1 \u2212 16) = 6 \u00b7 (\u221215) = \u221290\n<\/p>\n\n<h4>2. Obliczamy dziesi\u0105ty wyraz ci\u0105gu<\/h4>\n\n<p style=\"text-align:center;\">\na<sub>10<\/sub> = 6(10 \u2212 16) = 6 \u00b7 (\u22126) = \u221236\n<\/p>\n\n<h4>3. Obliczamy sum\u0119 dziesi\u0119ciu pocz\u0105tkowych wyraz\u00f3w<\/h4>\n\n<p>Korzystamy ze wzoru:<\/p>\n\n<p style=\"text-align:center;\">\nS<sub>n<\/sub> = (a<sub>1<\/sub> + a<sub>n<\/sub>) \u00b7 n \/ 2\n<\/p>\n\n<p>Podstawiamy dane:<\/p>\n\n<p style=\"text-align:center;\">\nS<sub>10<\/sub> = (\u221290 + (\u221236)) \u00b7 10 \/ 2\n<\/p>\n\n<p style=\"text-align:center;\">\nS<sub>10<\/sub> = (\u2212126) \u00b7 5 = \u2212630\n<\/p>\n\n<h3>Odpowied\u017a:<\/h3>\n<p>Suma dziesi\u0119ciu pocz\u0105tkowych wyraz\u00f3w wynosi <strong>\u2212630<\/strong>.<\/p>\n\n        <\/div>\n    <\/div>\n    \n<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>zadanie 11 \u2013 czerwiec 2016 (1pkt) Ci\u0105g (an) jest okre\u015blony wzorem an=6(n\u221216) dla n\u22651 . Suma dziesi\u0119ciu pocz\u0105tkowych wyraz\u00f3w tego ci\u0105gu jest r\u00f3wna: a) -54 b) -126 c) -630 d) -270<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"saved_in_kubio":false,"_uag_custom_page_level_css":"","_themeisle_gutenberg_block_has_review":false,"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[25,72,195,81,83],"tags":[23,71,131],"class_list":["post-1274","post","type-post","status-publish","format-standard","hentry","category-ciag-arytmetyczny","category-czerwiec-2016","category-suma-poczatkowych-wyrazow-ciagu-ciag-arytmetyczny","category-zadania-maturalne","category-zadania-tematami","tag-ciag-arytmetyczny","tag-czerwiec-2016","tag-suma-poczatkowych-wyrazow-ciagu"],"jetpack_featured_media_url":"","uagb_featured_image_src":{"full":false,"thumbnail":false,"medium":false,"medium_large":false,"large":false,"1536x1536":false,"2048x2048":false,"kubio-fullhd":false,"woocommerce_thumbnail":false,"woocommerce_single":false,"woocommerce_gallery_thumbnail":false},"uagb_author_info":{"display_name":"adminmymatma","author_link":"https:\/\/mymatma.pl\/?author=1"},"uagb_comment_info":0,"uagb_excerpt":"zadanie 11 \u2013 czerwiec 2016 (1pkt) Ci\u0105g (an) jest okre\u015blony wzorem an=6(n\u221216) dla n\u22651 . Suma dziesi\u0119ciu pocz\u0105tkowych wyraz\u00f3w tego ci\u0105gu jest r\u00f3wna: a) -54 b) -126 c) -630 d) -270","jetpack_sharing_enabled":true,"_links":{"self":[{"href":"https:\/\/mymatma.pl\/index.php?rest_route=\/wp\/v2\/posts\/1274","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/mymatma.pl\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/mymatma.pl\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/mymatma.pl\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/mymatma.pl\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=1274"}],"version-history":[{"count":1,"href":"https:\/\/mymatma.pl\/index.php?rest_route=\/wp\/v2\/posts\/1274\/revisions"}],"predecessor-version":[{"id":1275,"href":"https:\/\/mymatma.pl\/index.php?rest_route=\/wp\/v2\/posts\/1274\/revisions\/1275"}],"wp:attachment":[{"href":"https:\/\/mymatma.pl\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=1274"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/mymatma.pl\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=1274"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/mymatma.pl\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=1274"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}