{"id":1252,"date":"2025-12-22T11:54:55","date_gmt":"2025-12-22T10:54:55","guid":{"rendered":"http:\/\/mymatma.pl\/?p=1252"},"modified":"2025-12-22T11:55:42","modified_gmt":"2025-12-22T10:55:42","slug":"zadanie-108","status":"publish","type":"post","link":"https:\/\/mymatma.pl\/?p=1252","title":{"rendered":"Zadanie 108"},"content":{"rendered":"\n<p><strong>zadanie 15 \u2013 maj 2020 (1 pkt)<\/strong><\/p>\n\n\n\n<p>W ci\u0105gu arytmetycznym (a<sub>n<\/sub>) , okre\u015blonym dla n\u22651 , czwarty wyraz jest r\u00f3wny 3 , a r\u00f3\u017cnica tego ci\u0105gu jest r\u00f3wna 5 . Suma a<sub>1<\/sub>+a<sub>2<\/sub>+a<sub>3<\/sub>+a<sub>4 <\/sub>jest r\u00f3wna:<\/p>\n\n\n\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-28f84493 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p>a) -42<\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p>b) -36<\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p>c) -18<\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<p>d) 6<\/p>\n<\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-28f84493 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n    <div class=\"premium-wrapper-odp\" id=\"odp_69e22b376e562\">\n        <button class=\"premium-btn-odp\"\n                data-id=\"odp_69e22b376e562\"\n                style=\"margin-top:10px; padding:12px 20px; background:#28a745; color:#fff; border-radius:25px; border:none; cursor:pointer; font-weight:bold;\">\n            Poka\u017c odpowied\u017a\n        <\/button>\n\n        <div class=\"premium-content-odp\" style=\"display:none; padding:15px; border:1px solid #28a745; margin-top:10px; background:#e6ffe6; border-radius:25px;\">\n            \nPrawid\u0142owa odpowied\u017a to b) -36.\n        <\/div>\n    <\/div>\n    \n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n    <div class=\"premium-wrapper-wyjasnienie\" id=\"wyjasnienie_69e22b376e56e\">\n        <button class=\"premium-btn-wyjasnienie\"\n                data-id=\"wyjasnienie_69e22b376e56e\"\n                style=\"margin-top:10px; padding:12px 20px; background:#28a745; color:#fff; border-radius:25px; border:none; cursor:pointer; font-weight:bold;\">\n            Poka\u017c wyja\u015bnienie\n        <\/button>\n\n        <div class=\"premium-content-wyjasnienie\" style=\"display:none; padding:15px; border:1px solid #28a745; margin-top:10px; background:#e6ffe6; border-radius:25px;\">\n            \n<h3>Wyja\u015bnienie<\/h3>\n\n<p>W zadaniu podano, \u017ce:<\/p>\n\n<ul>\n  <li>a<sub>4<\/sub> = 3<\/li>\n  <li>r = 5<\/li>\n<\/ul>\n\n<p>Korzystamy ze wzoru na n\u2011ty wyraz ci\u0105gu arytmetycznego:<\/p>\n\n<p style=\"text-align:center;\">\na<sub>n<\/sub> = a<sub>1<\/sub> + (n \u2212 1)r\n<\/p>\n\n<p>Podstawiamy dane dla n = 4:<\/p>\n\n<p style=\"text-align:center;\">\na<sub>4<\/sub> = a<sub>1<\/sub> + 3r\n<\/p>\n\n<p style=\"text-align:center;\">\n3 = a<sub>1<\/sub> + 3\u00b75\n<\/p>\n\n<p style=\"text-align:center;\">\n3 = a<sub>1<\/sub> + 15\n<\/p>\n\n<p>Odejmujemy 15 od obu stron:<\/p>\n\n<p style=\"text-align:center;\">\na<sub>1<\/sub> = -12\n<\/p>\n\n<p>Teraz obliczamy sum\u0119 czterech pierwszych wyraz\u00f3w:<\/p>\n\n<p style=\"text-align:center;\">\nS<sub>4<\/sub> = a<sub>1<\/sub> + a<sub>2<\/sub> + a<sub>3<\/sub> + a<sub>4<\/sub>\n<\/p>\n\n<p>Wyznaczamy kolejne wyrazy:<\/p>\n\n<ul>\n  <li>a<sub>1<\/sub> = -12<\/li>\n  <li>a<sub>2<\/sub> = -12 + 5 = -7<\/li>\n  <li>a<sub>3<\/sub> = -7 + 5 = -2<\/li>\n  <li>a<sub>4<\/sub> = 3<\/li>\n<\/ul>\n\n<p>Dodajemy je:<\/p>\n\n<p style=\"text-align:center;\">\nS<sub>4<\/sub> = -12 &#8211; 7 &#8211; 2 + 3 = -36\n<\/p>\n\n<h3>Odpowied\u017a:<\/h3>\n<p>Suma czterech pierwszych wyraz\u00f3w wynosi <strong>-36<\/strong>.<\/p>\n\n        <\/div>\n    <\/div>\n    \n<\/div>\n<\/div>\n\n\n\n<p><\/p>\n","protected":false},"excerpt":{"rendered":"<p>zadanie 15 \u2013 maj 2020 (1 pkt) W ci\u0105gu arytmetycznym (an) , okre\u015blonym dla n\u22651 , czwarty wyraz jest r\u00f3wny 3 , a r\u00f3\u017cnica tego ci\u0105gu jest r\u00f3wna 5 . Suma a1+a2+a3+a4 jest r\u00f3wna: a) -42 b) -36 c) -18 d) 6<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"saved_in_kubio":false,"_uag_custom_page_level_css":"","_themeisle_gutenberg_block_has_review":false,"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[25,84,195,81,83],"tags":[23,196,131],"class_list":["post-1252","post","type-post","status-publish","format-standard","hentry","category-ciag-arytmetyczny","category-maj-2020","category-suma-poczatkowych-wyrazow-ciagu-ciag-arytmetyczny","category-zadania-maturalne","category-zadania-tematami","tag-ciag-arytmetyczny","tag-maj-2020","tag-suma-poczatkowych-wyrazow-ciagu"],"jetpack_featured_media_url":"","uagb_featured_image_src":{"full":false,"thumbnail":false,"medium":false,"medium_large":false,"large":false,"1536x1536":false,"2048x2048":false,"kubio-fullhd":false,"woocommerce_thumbnail":false,"woocommerce_single":false,"woocommerce_gallery_thumbnail":false},"uagb_author_info":{"display_name":"adminmymatma","author_link":"https:\/\/mymatma.pl\/?author=1"},"uagb_comment_info":0,"uagb_excerpt":"zadanie 15 \u2013 maj 2020 (1 pkt) W ci\u0105gu arytmetycznym (an) , okre\u015blonym dla n\u22651 , czwarty wyraz jest r\u00f3wny 3 , a r\u00f3\u017cnica tego ci\u0105gu jest r\u00f3wna 5 . Suma a1+a2+a3+a4 jest r\u00f3wna: a) -42 b) -36 c) -18 d) 6","jetpack_sharing_enabled":true,"_links":{"self":[{"href":"https:\/\/mymatma.pl\/index.php?rest_route=\/wp\/v2\/posts\/1252","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/mymatma.pl\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/mymatma.pl\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/mymatma.pl\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/mymatma.pl\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=1252"}],"version-history":[{"count":2,"href":"https:\/\/mymatma.pl\/index.php?rest_route=\/wp\/v2\/posts\/1252\/revisions"}],"predecessor-version":[{"id":1255,"href":"https:\/\/mymatma.pl\/index.php?rest_route=\/wp\/v2\/posts\/1252\/revisions\/1255"}],"wp:attachment":[{"href":"https:\/\/mymatma.pl\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=1252"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/mymatma.pl\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=1252"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/mymatma.pl\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=1252"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}